WAEC SSCE - General Mathematics - 2016 (Objective)

Question 1 Report

A straight line passes through the points P(1,2) and Q(5,8). Calculate the gradient of the line PQ

$\frac{3}{5}$

$\frac{2}{3}$

$\frac{3}{2}$ Correct answer

$\frac{5}{3}$

Answer Details

The gradient of a line is the measure of its steepness, or slope. To find the gradient of the line PQ, we need to use the formula: Gradient (m) = change in y / change in x We can calculate the change in y by subtracting the y-coordinate of point P from the y-coordinate of point Q: 8 - 2 = 6 Similarly, we can calculate the change in x by subtracting the x-coordinate of point P from the x-coordinate of point Q: 5 - 1 = 4 Therefore, the gradient of the line PQ is: Gradient (m) = change in y / change in x = 6 / 4 = 3/2 Therefore, the answer is option C: $\frac{3}{2}$.

Read lesson note on Graphs Of Linear And Quadratic Functions (WAEC)






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