WAEC SSCE - General Mathematics - 2004 (Objective)

Question 1 Report

Given that x + y = 7 and 3x-y = 5, evaluate $\frac{y}{2}-3$.

-1 Correct answer

Answer Details

To solve this problem, we first need to find the values of x and y, and then substitute them into the expression $\frac{y}{2}-3$. From the given equations, we can use the elimination method to solve for x and y. Multiplying the second equation by 2 and adding it to the first equation, we get: 2(3x-y) + (x+y) = 11x = 17 x = 17/11 Substituting x into the first equation, we get: y = 7 - x = 7 - 17/11 = 60/11 Now we can substitute these values into the expression $\frac{y}{2}-3$: $\frac{y}{2}-3 = \frac{60/11}{2} - 3 = \frac{30}{11} - \frac{33}{11} = -\frac{3}{11}$ Therefore, the answer is -1.






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