A stone is thrown vertically upward and distance, S metres after t seconds is given by S = 12t + \(\frac{5}{2t^2}\) - t\(^3\). Calculate the maximum height ...

Assessment: WAEC SSCE - Further Mathematics - 2021 (Objective) Subject: Further Mathematics

Question 1 Report

A stone is thrown vertically upward and distance, S metres after t seconds is given by S = 12t + \(\frac{5}{2t^2}\) - t\(^3\).

Calculate the maximum height reached.

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