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Solve (\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)
Question 1
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Solve (\(\frac{1}{9}\))\(^{x + 2}\) = 243\(^{x - 2}\)
\(\frac{7}{5}\)
\(\frac{6}{7}\)
\(\frac{-7}{6}\)
\(\frac{-6}{7}\)
Answer Details
Read lesson note on Surds (WAEC)
Surds
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