What is the mean of the data t, 2t - 1, t -..

Question 1 Report

What is the mean of the data t, 2t - 1, t - 2, 2t - 1, 4t and 2t + 2?

2t - 1

\frac{2}{3}

t + 1

2t -

\frac{1}{3}

Answer Details

$\frac{t + 2 t - 1 + t - 2 + 2 t - 1 + 4 t + 2 t + 2}{6}$
= $\frac{12 t - 2}{6}$
= $\frac{12 t}{6}$ - $\frac{2}{6}$
= 2t - $\frac{1}{3}$