If p varies inverse as the square of q and p = 8 when q =4, find q when p = 32

Question 1 Report

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Answer Details

P $α$ $\frac{1}{q^{2}}$
p = $\frac{k}{q^{2}}$
k = pq2
k = 8 x 42
k = 8 x 16 = 128
find k = pq2
q2 = $\frac{k}{p}$
q = $\frac{k}{p}$
q = $\frac{128}{32}$
q = √4
q = $\pm$ 2

Read lesson note on Solution Of Linear Equations (WAEC)

Solution Of Linear Equations

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