Question 1 Report
(−2123) ( − 2 1 2 3 ) + (pqrs) ( p q r s ) = (1001) ( 1 0 0 1 ) . What is the value of r?
Answer Details
-2p + r = 1.......(i) 2p + 3r = 0.......(ii) r - 1 + 2p ........(iii) 2p + 3(1 + 2p) = 0 2p + 3(1 + 2p) = 0 2p + 3 + 6p = 0 3 - 8p = 0 → → 8p = 3 p = 38 3 8 6 = 1 - 2 38 3 8 = 1 - 68 6 8 8−68 8 − 6 8 = 28 2 8 = 14
Find the values of x and y respectively if ⎛⎜⎝10−1−122⎞⎟⎠ ( 1 0 − 1 − 1 2 2 ) + ⎛⎜⎝x1−10y−2⎞⎟⎠ ( x 1 − 1 0 y − 2 ) = ⎛⎜⎝−21−2−1−300⎞⎟⎠
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