If logX12 l o g X 1 2 64 = 3, find the value of x.

If $log{X}^{\frac{1}{2}}$ 64 = 3, find the value of x.

Answer Details

$log{X}^{\frac{1}{2}}$ 64 = 3, find the value of X
recall that X = 10p
log10X = P
64 = $X^{\frac{1}{2}}$
43 = $X^{\frac{1}{2}}$
$4^{3\times \frac{1}{2}}$ = $X^{\frac{1}{2}\times \frac{1}{3}}$
4 = $X^{\frac{1}{2}}$
(4)2 = $X^{\frac{1}{2}\times 2}$
x = 16