If 10112 + x7 = 2510, solve for X.

Assessment: JAMB UTME - Mathematics - 1998 Subject: General Mathematics

Question 1 Report

If 10112 + x7 = 2510, solve for X.

Answer Details

10112 + x7 = 2510 = 10112 = 1 x 23 + 0 x 22 + 1 x 21 + 1 x 2o
= 8 + 0 + 2 + 1
= 1110
x7 = 2510 - 1110
= 1410
7 14 7 2 R 0 0 R 2
X = 207

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