Evaluate \[ \frac{1}{0.03} \div \frac{1}{0.024} \]⁻¹ correct to 2 decimal places

Assessment: JAMB UTME - Mathematics - 1998 Subject: General Mathematics

Question 1 Report

Evaluate \[ \frac{1}{0.03} \div \frac{1}{0.024} \]⁻¹ correct to 2 decimal places

Answer Details
[ 1 0.03  +  1 0.024 ]
= [ 1 0.03 × 0.024 ]-1
= [ 0.024 0.003 ]-1
=  0.03 0.024
=  30 24  = 1.25

Download The App On Google Playstore

Everything you need to excel in your exams

Green Bridge CBT Mobile App
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning