Find the value of k if k?3+?2 k 3 + 2 = k?3?2

Question 1 Report

Find the value of k if $\frac{k}{\sqrt{3} + \sqrt{2}}$ = k $\sqrt{3 - 2}$

3

2

√3

√2

Answer Details

$\frac{k}{\sqrt{3} + \sqrt{2}}$ = k $\sqrt{3 - 2}$
$\frac{k}{\sqrt{3} + \sqrt{2}}$ x $\frac{\sqrt{3} - \sqrt{2}}{\sqrt{3} - \sqrt{2}}$
= k $\sqrt{3 - 2}$
= k( $\sqrt{3} - \sqrt{2}$ )
= k $\sqrt{3 - 2}$
= k $\sqrt{3}$ - k $\sqrt{2}$
= k $\sqrt{3 - 2}$
k2 = $\sqrt{2}$
k = $\frac{2}{\sqrt{2}}$
= $\sqrt{2}$

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Surds (radicals)

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