Question 1 Report
If p + 1, 2P - 10, 1 - 4p2are three consecutive terms of an arithmetic progression, find the possible values of p
Answer Details
2p - 10 = p+1+1−4P22 p + 1 + 1 − 4 P 2 2 (Arithmetic mean) = 2(2p - 100 = p + 2 - 4P2) = 4p - 20 = p + 2 - 4p2 = 4p2 + 3p - 22 = 0 = (p - 2)(4p + 11) = 0 ∴ p = 2 or -411
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