In a recent zonal championship games involving 10 teams, teams X and Y were given probabilities 25 2 5 and 13 1 3 respectively of winning the gold in the fo...

In a recent zonal championship games involving 10 teams, teams X and Y were given probabilities $\frac{2}{5}$ and $\frac{1}{3}$ respectively of winning the gold in the football event. What is the probability that either team will win the gold?

Answer Details

p(x) = $\frac{2}{5}$ p(y) = $\frac{1}{3}$
p(x or y) = p(x ∪ y)
= p(x) + p(y)
= $\frac{2}{5}$ + $\frac{1}{3}$
= $\frac{11}{5}$