In a recent zonal championship games involving 10 teams, teams X and Y were given probabilities \( \frac{2}{5} \) and \( \frac{1}{3} \) respectively of winn...

Assessment: JAMB UTME - Mathematics - 1998 Subject: General Mathematics

Question 1 Report

In a recent zonal championship games involving 10 teams, teams X and Y were given probabilities \( \frac{2}{5} \) and \( \frac{1}{3} \) respectively of winning the gold in the football event. What is the probability that either team will win the gold?

Answer Details
p(x) =  2 5  p(y) =  1 3
p(x or y) = p(x ∪ y)
= p(x) + p(y)
=  2 5  +  1 3
= 

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