Question 1 Report
Find the positive value of x if the standard deviation of the numbers 1, x + 1 is 6
Answer Details
mean (x) = 1+x+1+2x+13 1 + x + 1 + 2 x + 1 3 = 3x+33 3 x + 3 3 = 1 + x X(X−X)(X−X)21−xx2x+1002x+1xx22x2 X ( X − X ) ( X − X ) 2 1 − x x 2 x + 1 0 0 2 x + 1 x x 2 2 x 2 S.D = √∑(x−7)2∑f ∑ ( x − 7 ) 2 ∑ f = √(6)2 ( 6 ) 2 = 2x23 2 x 2 3 = 2x2 = 18 x2 = 9 ∴ x = ± ± √9 9 = ± ± 3
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