Question 1 Report
Estimate the mode of the above frequency distribution
Answer Details
Class intervalsFClass boundary5−7174.5−9.510−14329.5−14.515−192514.5−19.520−242419.5−24.5 Class intervals F Class boundary 5 − 7 17 4.5 − 9.5 10 − 14 32 9.5 − 14.5 15 − 19 25 14.5 − 19.5 20 − 24 24 19.5 − 24.5 mode = 9 + D1D2+D1 D 1 D 2 + D 1 x C = 9.5 + 5(32−17)2(32)−17−25 5 ( 32 − 17 ) 2 ( 32 ) − 17 − 25 = 9.5 + 7527 75 27 = 12.27 ≈ ≈ 2.3
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