In the diagram, QTR is a straight line and < PQT = 30? ? . find the sin of < PTR

Question 1 Report

In the diagram, QTR is a straight line and < PQT = 30 $^{\circ}$ . find the sin of < PTR

\frac{8}{15}

\frac{2}{3}

\frac{3}{4}

\frac{15}{16}

Answer Details

$\frac{10}{\sin 30^{o}} = \frac{15}{\sin x} = \frac{10}{0.5} = \frac{15}{\sin x}$

$\frac{15}{20} = \sin x$

sin x = $\frac{15}{20} = \frac{3}{4}$

N.B x = < PRQ

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