Question 1 Report
If x is a positive real number, find the range of values for which \( \frac{1}{3x} + \frac{1}{2} > \frac{1}{4x} \)
Answer Details
13x 1 3 x + 12 1 2 > 14x 1 4 x = 2+3x6x 2 + 3 x 6 x > 14x 1 4 x = 4(2 + 3x) > 6x = 12x2 - 2x = 0 = 2x(6x - 1) > 0 = x(6x - 1) > 0 Case 1 (-, -) = x < 0, 6x -1 < 0
= x < 0, x < 16 1 6 = x < 16 1 6 (solution)
Case 2 (+, +) = x > 0, 6x -1 > 0 = x > 0, x > 16 1 6 Combining solutions in cases(1) and (2)= x > 0, x < 16 1 6 = 0 < x < 16
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