Evaluate ∫π2 2 π (sec2 x - tan2x)dx

Question 1 Report

Evaluate ∫ $_{2}^{π}$ (sec2 x - tan2x)dx

\frac{π}{2}

π

- 2

\frac{π}{3}

π

+ 2

Answer Details

∫ $_{2}^{π}$ (sec2 x - tan2x)dx
∫ $_{2}^{π}$ dx = [X] $_{2}^{π}$
= $π$ - 2 + c
when c is an arbitrary constant of integration