Ana ebu...
|
Pịa ma Jide iji Dọkpụrụ Ya |
|||
|
Pịa Ebe a ka Imechi |
|||
Ajụjụ 1 Ripọtì
Akọwa Nkọwa
Ajụjụ 2 Ripọtì
Akọwa Nkọwa
Ajụjụ 3 Ripọtì
Akọwa Nkọwa
Ajụjụ 4 Ripọtì
Ajụjụ 5 Ripọtì
Evaluate \( \frac{(18)^{\frac{3}{4}}-(27)^3}{3\times 2^3} \)
Ajụjụ 6 Ripọtì
Akọwa Nkọwa
Ajụjụ 8 Ripọtì
For what value of x is the tangent to the curve \(y = x^2 - 4x + 3\) parallel to the x-axis?
Akọwa Nkọwa
Ajụjụ 10 Ripọtì
In the diagram, the base diameter is 14cm while the height is 12cm. Calculate the total surface area if the cylinder has both a base and a top.[\( \pi \frac{22}{7} \)]
Akọwa Nkọwa
Ajụjụ 11 Ripọtì
In the diagram, find PQ if the area of triangle PQR is 35cm2
Akọwa Nkọwa
Ajụjụ 13 Ripọtì
The graph of f(x) = x2 - 5x + 6 crosses the x-axis at the points
Akọwa Nkọwa
Ajụjụ 14 Ripọtì
Find the area bounded by the curve \(y = 3x^2 - 2x + 1\), the coordinates \(x = 1\) and \(x = 3\) and the x-axis
Akọwa Nkọwa
Ajụjụ 15 Ripọtì
Akọwa Nkọwa
Ajụjụ 16 Ripọtì
Express \( \frac{5x-12}{(x-2)(x-3)} \) in partial fractions
Akọwa Nkọwa
5x−12(x−2)(x−3)=Ax−2+Bx−3
= A(x−3)+B(x−2)(x−2)(x−3)
⟹5x−12=Ax−3A+Bx−2B
A+B=5...(i)
−(3A+2B)=−12⟹3A+2B=12...(ii)
From (i), A=5−B
3(5−B)+2B=12
15−3B+2B=12⟹B=3
A+3=5⟹A=2
5x−12(x−2)(x−3)=2x−2+3x−3
Ajụjụ 17 Ripọtì
Solve the inequality \( (x - 3)(x - 4) \le 0 \)
Akọwa Nkọwa
Ajụjụ 18 Ripọtì
If \(x - 1\) and \(x + 1\) are both factors of the equation \(x^3 + px^2 + qx + 6 = 0\), evaluate \(p\) and \(q\)
Akọwa Nkọwa
Ajụjụ 19 Ripọtì
Find the sum to infinity of the following sequence 1. \( \frac{9}{10} \), 2. (\( \frac{9}{10} \)), 3. (\( \frac{9}{10} \))
Akọwa Nkọwa
Ajụjụ 20 Ripọtì
Akọwa Nkọwa
Ajụjụ 21 Ripọtì
Ajụjụ 22 Ripọtì
| Age in years | 13 | 14 | 15 | 16 | 17 |
| No. of students | 3 | 10 | 30 | 42 | 15 |
The frequency distribution above shows the ages of students in a secondary school. In a pie chart constructed to represent the data, the angles corresponding to the 15 years old is
Akọwa Nkọwa
Ajụjụ 23 Ripọtì
Akọwa Nkọwa
Ajụjụ 24 Ripọtì
Akọwa Nkọwa
Ajụjụ 25 Ripọtì
Two variables x and y are such that \( \frac{dy}{dx} = 4x - 3 \) and y = 5 when x = 2. Find y in terms of x
Akọwa Nkọwa
Ajụjụ 27 Ripọtì
Akọwa Nkọwa
Ajụjụ 28 Ripọtì
Find the distance between two towns p(45\(^{o}\)N, 30\(^{o}\)W) and Q(15\(^{o}\)S, 30\(^{o}\)W) if the radius of the earth is 7000km. [\(\pi = \frac{22}{7}\)]
Akọwa Nkọwa
Ajụjụ 29 Ripọtì
Let \(p\) be a probability function on set \(S\), where \(S = (a_1, a_2, a_3, a_4)\). Find \(P(a_1)\) if \(P(a_2) = \frac{1}{3}\), \(p(a_3) = \frac{1}{6}\) and \(p(a_4) = \frac{1}{5}\)
Akọwa Nkọwa
Ajụjụ 31 Ripọtì
| Class Interval | Frequency | Class boundaries | Class Mid-point |
| \(1.5 - 1.9\) | \(2\) | \(1.45 - 1.95\) | \(1.7\) |
| \(2.0 - 2.4\) | \(21\) | \(1.95 - 2.45\) | \(2.2\) |
| \(2.5 - 2.9\) | \(4\) | \(2.45 - 2.95\) | \(2.7\) |
| \(3.0 - 2.9\) | \(15\) | \(2.95 - 3.45\) | \(3.2\) |
| \(3.5 - 3.9\) | \(10\) | \(3.45 - 3.95\) | \(3.7\) |
| \(4.0 - 4.4\) | \(5\) | \(3.95 - 4.45\) | \(4.2\) |
| \(4.5 - 4.9\) | \(3\) | \(4.45 - 4.95\) | \(4.7\) |
The median of the distribution above is
Akọwa Nkọwa
Ajụjụ 32 Ripọtì
Akọwa Nkọwa
Ajụjụ 33 Ripọtì
Akọwa Nkọwa
Ajụjụ 34 Ripọtì
Akọwa Nkọwa
Ajụjụ 36 Ripọtì
Akọwa Nkọwa
Ajụjụ 37 Ripọtì
If \(a \ast b = +\sqrt{ab}\), evaluate \(2 \ast (12 \ast 27)\)
Akọwa Nkọwa
Ajụjụ 38 Ripọtì
| Class Interval | Frequency | Class boundaries | Class Mid−point |
| \(1.5-1.9\) | \(2\) | \(1.45-1.95\) | \(1.7\) |
| \(2.0-2.4\) | \(21\) | \(1.95-2.45\) | \(2.2\) |
| \(2.5-2.9\) | \(4\) | \(2.45-2.95\) | \(2.7\) |
| \(3.0-2.9\) | \(15\) | \(2.95-3.45\) | \(3.2\) |
| \(3.5-3.9\) | \(10\) | \(3.45-3.95\) | \(3.7\) |
| \(4.0-4.4\) | \(5\) | \(3.95-4.45\) | \(4.2\) |
| \(4.5-4.9\) | \(3\) | \(4.45-4.95\) | \(4.7\) |
Find the mode of the distribution above to find the mode of the distribution.
Akọwa Nkọwa
Mode = a + (b - a)(fm - Fb)
2Fm - Fa - Fb
= 3.0 + (3.4?3)(15?4)2(15)?4?10
= 3 + (6.4)(11)30?14
= 3 + 4.416
= 3 + 0.275
= 3.275
= 3.3cm
Ajụjụ 39 Ripọtì
Find T in terms of K, Q and S if S = 2r\( \pi \)QT + K)
Akọwa Nkọwa
T = s24Qπr2 - k
Ajụjụ 40 Ripọtì
If \(x = \begin{pmatrix}1 & 2 \\ 0 & 3\end{pmatrix}\) and \(y = \begin{pmatrix}2 & 1 \\ 4 & 3\end{pmatrix}\). Find \(xy\).
Akọwa Nkọwa
Ajụjụ 41 Ripọtì
Akọwa Nkọwa
Ajụjụ 42 Ripọtì
PT is a tangent to the circle TYZX. YT = YX and < PTX = 50o. Calculate < TZY
Ajụjụ 43 Ripọtì
Use the graph of the curve \(y = f(x)\)to solve the inequality \(f(x) \le 0\)
Akọwa Nkọwa
Combining solutions
= x ≤ 1; 1 ≥ x ≥ 2
Ajụjụ 45 Ripọtì
Akọwa Nkọwa
Ajụjụ 47 Ripọtì
Akọwa Nkọwa
Ị ga-achọ ịga n'ihu na omume a?