A bus travelling at 15ms-1 accelerates uniformly at 4ms-2, what is the distance covered in 10s?
Question 1 Report
A bus travelling at 15ms-1 accelerates uniformly at 4ms-2, what is the distance covered in 10s?
Answer Details
The initial velocity of the bus, u = 15m/s, the acceleration, a = 4m/s2, and the time, t = 10s. We can use the formula: distance = ut + (1/2)at2 Substituting the values given: distance = (15m/s)(10s) + (1/2)(4m/s2)(10s)2 distance = 150m + 200m distance = 350m Therefore, the distance covered in 10 seconds is 350m. Answer is the correct answer.
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