The apparent weight of a body wholly immersed in water is 32N and its weight in air is 96N. Calculate the volume of the body. (Density of water = 1000kgm-3,...

Answer Details

When a body is immersed in water, it experiences an upthrust force, which reduces its weight. According to Archimedes' principle, this upthrust force is equal to the weight of the water displaced by the body. Therefore, we can use the given data to find the volume of the body as follows: Weight of body in air = 96N Apparent weight of body in water = 32N Upthrust force = Weight of water displaced = Weight of body in air - Apparent weight of body in water Upthrust force = 96N - 32N = 64N Now, we can use the formula for upthrust force to find the volume of the body: Upthrust force = Volume of body x Density of water x g 64N = Volume of body x 1000kgm^-3 x 10ms^-2 Volume of body = 64N / (1000kgm^-3 x 10ms^-2) = 6.4 x 10^-3m³ Therefore, the volume of the body is 6.4 x 10^-3m³.