A wooden block of mass 1.6kg rest on a rough horizontal surface, if the limiting friction force between the block and the surface is 8N. Calculate the coeff...

A wooden block of mass 1.6kg rest on a rough horizontal surface, if the limiting friction force between the block and the surface is 8N. Calculate the coefficient of friction. (g = 10ms^-2)

Answer Details

The coefficient of friction (μ) is the ratio of the frictional force (F) to the normal force (N) between two surfaces in contact. In this case, the normal force is equal to the weight of the block, which is given by: N = mg where m is the mass of the block and g is the acceleration due to gravity (10ms^-2). N = 1.6 kg x 10 ms^-2 = 16 N The limiting friction force (F) is given as 8N. Therefore, we have: F = μN Substituting the values we have obtained, we can solve for μ as follows: μ = F/N = 8N/16N = 0.5 Therefore, the coefficient of friction is 0.5. Answer: 0.5