The chances of three independent events X, Y, Z occurring are 12, 23, 14 respectively. What are the chances of Y and Z only occurring?
Answer Details
Chance of x = 12 Change of Y = 23 Chance of Z = 14 Chance of Y and Z only occurring = Pr (Y ? Z ? Xc) where Xc = 1 - Pr(X) 1 = 12 = 112 = Pr(Y) x Pr(Z) x Pr(Xc) = 23 x 14 x 12 = 112