Question 1 Report
Integrate 1−xx3 with respect to x
x−x2x4 x − x 2 x 4 + k
1x−12x2 1 x − 1 2 x 2 + k
13x2−12x 1 3 x 2 − 1 2 x + k
Answer Details
∫1−xx3 ∫ 1 − x x 3 = ∫1x3−∫xx3 ∫ x 3 1 − ∫ x 3 x = x-3 dx - x-2dx= 12x2+1x
If 9(x - 12 1 2 ) 3x2
Solve without using tables log5(62.5) - log5(12 1 2 )
simplify 1√3−2 1 √ 3 − 2 - 1√3+2
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change 7110 to base 8
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