Question 1 Report
Solve for y in the equation 101 x 5(2x - 2) x 4(y - 1) = 1
Answer Details
10y x 5(2y - 2) x 4(y - 1) = 1 but 10y - (5 x 2)y = 5y x 2y = (Law of indices) 5y x 2y x 5(2y - 2) x 4(y - 1) = 1 but 4(y - 1) = 22(y - 1) = 2y - 2 (Law of indices) 5y x 5(2y -2) x 2(- 2) = 1 5(3y -2) x 2y x 2(2y -2) = 1 = 5(3y -2) x 2(3y -2) = 1 But ao = 1 10(3y -2) = 10o 3y - 2 = 0 ? y = 23
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