Question 1 Report
Solve the inequality y2 - 3y > 18
Answer Details
y2 - 3y > 18 = 3y - 18 > 0 y2 - 6y + 3y - 18 > 0 = y(y - 6) + 3 (y - 6) > 0 = (y + 3) (y - 6) > 0 Case 1 (+, +) → → (y + 3) > 0, (y - 6) > 0 = y > -3 y > 6 Case 2 (-, -) → → (y + 3) < 0, (y - 6) < 0
= y < -3, y < 6
Combining solution in case 1 and Case 2= x < -3y < 6
= -3 < y < 6
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