Question 1 Report
In the diagram, O is the centre of the circle and POQ a diameter. If POR = \(96^\circ\), find the value of ORQ.
< ROQ = 180 - 86 = 84
OQR = Isosceles
R = Q
R + Q + 84 = 180(angle in a )
2R = 96 since R = Q
R = 48
ORQ = 48
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