In the diagram, O is the centre of the circle and POQ a diameter. If POR = 96? ? , find the value of ORQ.

Assessment: JAMB UTME - Mathematics - 1993 Subject: General Mathematics

Question 1 Report

In the diagram, O is the centre of the circle and POQ a diameter. If POR = 96 $^{\circ}$ , find the value of ORQ.

84

^{\circ}

48

^{\circ}

45

^{\circ}

42

^{\circ}

Answer Details

OQ = OR = radii

< ROQ = 180 - 86 = 84 $^{\circ}$

$△$ OQR = Isosceles

R = Q

R + Q + 84 = 180(angle in a $△$ )

2R = 96 since R = Q

R = 48 $^{\circ}$

ORQ = 48 $^{\circ}$

Related Questions

Everything you need to excel in JAMB, WAEC & NECO