If \( \sin \theta = \cos \theta \), find \( \theta \) between 0o and 360o
Answer Details
sin θ = cos θ 0 ≤θ≤ 360o The acute angle where sin θ = cos θ = 45o But at the fourth Quadrant Cos θ = +ve at the 4th quadrant, value with respect to Q is (360 - Q) where Q = acute angle (360 - 45) = 315o The two solution are 45o, 315o