In the diagram, PQRs is a circle with 0 as centre and PQ/RT. If RTS = 32∘ ? . Find PSQ

In the diagram, PQRs is a circle with 0 as centre and PQ/RT. If RTS = ${}^{\circ }$. Find PSQ

Answer Details

< PSO = $\frac{1}{2}$ < SOQ = $\frac{1}{2}$(180) = 90${}^{\circ }$

< RTS = < PQS = 32${}^{\circ }$ (Alternative angle)

< PSQ = 90 - < PSQ = 90${}^{\circ }$ - 32${}^{\circ }$

= 58${}^{\circ }$