If two angles of a triangle are 30o each and the longest side is 10cm. Calculate the length of each of the other sides

If two angles of a triangle are 30o each and the longest side is 10cm. Calculate the length of each of the other sides

Answer Details

102 = 2x2 - 2x2 cos 120o (Cosine rule)
100 = 242 - 2x2 - 2x2 x -$\frac{1}{2}$
100 = 3x2 + x2
= 3x2
x = $\sqrt{\frac{100}{3}}$
= $\frac{10}{\sqrt{3}}$ x $\frac{3}{\sqrt{3}}$
x = 10$\frac{3}{3}$cm