In the diagram, QPS = SPR, PR = 9cm. PQ = 4..

Question 1 Report

In the diagram, QPS = SPR, PR = 9cm. PQ = 4cm and QS = 3cm, find SR.

\frac{3}{4}

\frac{3}{8}

\frac{3}{8}

\frac{3}{8}

Answer Details

Using angle bisector theorem: line PS bisects angle QPR

QS/QP = SR/PR

3/4 = SR/g

4SR = 27

SR = $\frac{27}{4}$

= 6 $\frac{3}{4}$ cm