If √x2+9 x 2 + 9 = x + 1, solve for x

Question 1 Report

If $\sqrt{x^{2} + 9}$ = x + 1, solve for x

Answer Details

$\sqrt{x^{2} + 9}$ = x + 1
x2 + 9 = (x + 1)2 + 1
0 = x2 + 2x + 1 - x2 - 9
= 2x - 8 = 0
2(x - 4) = 0
x = 4