A coin place below a rectangular glass block of thickness 9cm and refractive index 1.5 is viewed vertically above the block. The apparent displacement of th...

Answer Details

The apparent displacement of the coin is 3 cm. The rectangular glass block with a thickness of 9 cm and a refractive index of 1.5 will refract light passing through it. When the coin is placed beneath the block and viewed vertically from above, the light from the coin will refract as it passes through the glass block, making the coin appear to be displaced from its original position. The amount of displacement will depend on the thickness of the glass block and the refractive index of the material. Using the formula for the apparent depth of an object submerged in a material with a different refractive index, we can calculate the displacement: Apparent depth = Actual depth / Refractive index In this case, the actual depth of the coin is the thickness of the glass block, which is 9 cm. The refractive index of the glass block is 1.5. Therefore, the apparent depth of the coin will be: Apparent depth = 9 cm / 1.5 = 6 cm However, this only calculates the apparent depth of the coin, not its apparent displacement. To find the displacement, we need to subtract the actual depth of the coin (which is 0 cm) from the apparent depth: Displacement = Apparent depth - Actual depth Displacement = 6 cm - 0 cm Displacement = 6 cm So the coin will appear to be displaced by 6 cm. However, since the coin is placed at the center of the block, the displacement will only be half of this value, or 3 cm, in any direction. Therefore, the correct answer is 3 cm.