A bead traveling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01kg and the coefficient of friction between the be...

Assessment: JAMB UTME - Physics - 2002 Subject: Physics

Question 1 Report

A bead traveling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01kg and the coefficient of friction between the bead and the wire is 0.1 determine the work done by the friction
Answer Details
The work done by friction can be found by calculating the force of friction and multiplying it by the distance the bead traveled. The force of friction can be found using the formula: force of friction = coefficient of friction * normal force where the normal force is the force exerted by the wire on the bead, which is equal and opposite to the weight of the bead. normal force = weight of the bead = mass * gravity where gravity is the acceleration due to gravity, approximately equal to 9.81 m/s^2. So, the normal force is: normal force = 0.01 kg * 9.81 m/s^2 = 0.0981 N And the force of friction is: force of friction = 0.1 * 0.0981 N = 0.00981 N Now, to find the work done by friction, we multiply the force of friction by the distance traveled: work done by friction = force of friction * distance traveled In this case, the distance traveled is 0.2 m. So: work done by friction = 0.00981 N * 0.2 m = 0.001962 J Therefore, the work done by friction is 2 × 10^-3 J.

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