A current of 0.5 A flowing 3h Deposits 2g of metal during electrolysis. The quantity of the same metal that would be deposited by the currents of 1.5A flowi...
A current of 0.5 A flowing 3h Deposits 2g of metal during electrolysis. The quantity of the same metal that would be deposited by the currents of 1.5A flowing in 1h is
Answer Details
From Faradays Law, mass deposited during electrolysis is given by M = ItZ => Z = M/(It)
=
__2
0.5x3x60x60
For a current of 1.5A flowing for 1h, the mass M, deposited is given by M= ZiT = 2 / (0.5x3x60x60) x 0.5x1x60x60 / 1 = 2.0g M = 2.0g