Question 1 Report
∫π2−π2 ∫ − π 2 π 2 cosx dx
Answer Details
∫π2−π2 ∫ − π 2 π 2 cosx [sinx]π2π2 [ s i n x ] π 2 π 2 = sinπ2 π 2 - (-sin π2 π 2 ) = sin π2 π 2 + sin π2 π 2 = 2 sin π2 π 2 = 2 sin 1.5714 = 2(0.2704) = 0.5 = 1
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