Evaluate ∫21 ∫ 1 2 (6x2 - 2x)dx

Question 1 Report

Evaluate $\int_{1}^{2}$ (6x2 - 2x)dx

Answer Details

$\int_{1}^{2}$ (6x2 - 2x)dx
= [ $\frac{6 x^{3}}{3} - \frac{2 x^{2}}{2}$ ]2
= [2x3 - x2]2
= (2(2)3 - 4 - 2 + 1
= 16 - 4 - 2 + 1
= 17 - 6
= 11