Question 1 Report
Evaluate ∫21(6x2−2x)dx
Answer Details
∫21(6x2−2x)dx=[6x33−2x22]21=[2x3−x2]21 ∫ 1 2 ( 6 x 2 − 2 x ) d x = [ 6 x 3 3 − 2 x 2 2 ] 1 2 = [ 2 x 3 − x 2 ] 1 2 = [2(2)3 - (2)2] – [2(1)3 - (1)2] = [16-4] – [2-1] = 12 – 1 = 11
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if X = {n2 + 1 : n = 0, 2, 3} and y = {n + 1 : n = 2, 3, 4, 5}, find x ∩ y
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