Question 1 Report
Evaluate ∫π2−π2cosxdx
Answer Details
∫π2−π2cosxdx=[sinx]π2−π2=sinπ2−sin−π2 ∫ − π 2 π 2 c o s x d x = [ s i n x ] − π 2 π 2 = s i n π 2 − s i n − π 2 = sin90 – sin-90 = sin90 – sin270 = 1 – (-1) = 1+1 = 2