(a) Sketch the magnetic flux pattern around a long; straight, current-carrying wire (b) State two methods by which the sensitivity of a moving-coil galvanom...

Assessment: WAEC SSCE - Physics - 1999 (Essay) Subject: Physics

Question 1 Report

(a) Sketch the magnetic flux pattern around a long; straight, current-carrying wire

(b) State two methods by which the sensitivity of a moving-coil galvanometer can be increased.

(c) A series RLC circuit comprises a 100-\(\Omega\) resistor, a 3-H inductor and a 4-\(\mu\)f capacitor. The a.c source of tile circuit has an e.m.f of 100V and a frequency of 160 Hz.

(i) Draw the circuit diagram of the arrangement. Calculate the:

(ii) capacitive reactance;

(iii) inductive reactance:

(iv) impedance of the circuit;

(v) current in the circuit;

(vi) average power dissipated in the circuit.

Answer Details

(a) Magnetic flux pattern around a long straight current-carrying wire

The wire carries current out of the plane of the paper, as indicated by the dot. The magnetic field lines are concentric circles centred on the wire. Their direction is anticlockwise, given by the right-hand grip rule.

figure
Concentric magnetic flux lines around a straight wire carrying current out of the page.

(b) The sensitivity of a moving-coil galvanometer can be increased by:

  1. using a weaker control spring, so that the restoring torque is smaller;
  2. using a stronger magnet to increase the magnetic flux density.

(c) Given: \(R=100\,\Omega\), \(L=3\,\text{H}\), \(C=4\,\mu\text{F}=4\times10^{-6}\,\text{F}\), \(V=100\,\text{V}\), and \(f=\dfrac{160}{\pi}\,\text{Hz}\).

(i) Series RLC circuit

figure
A 100 Ω resistor, 3 H inductor and 4 μF capacitor connected in series to an a.c. source.

(ii) Capacitive reactance

\[X_C=\frac{1}{2\pi fC}=\frac{1}{2\pi\left(\dfrac{160}{\pi}\right)\left(4\times10^{-6}\right)}=781.25\,\Omega\]

\[\boxed{X_C\approx781\,\Omega}\]

(iii) Inductive reactance

\[X_L=2\pi fL=2\pi\left(\dfrac{160}{\pi}\right)(3)=960\,\Omega\]

\[\boxed{X_L=960\,\Omega}\]

(iv) Impedance

\[Z=\sqrt{R^2+(X_L-X_C)^2}\]

\[Z=\sqrt{100^2+(960-781.25)^2}=204.8\,\Omega\]

\[\boxed{Z\approx205\,\Omega}\]

(v) Current in the circuit

\[I=\frac{V}{Z}=\frac{100}{204.8}=0.488\,\text{A}\]

\[\boxed{I\approx0.49\,\text{A}}\]

(vi) Average power dissipated

Only the resistor dissipates average power:

\[P=I^2R=(0.488)^2(100)=23.8\,\text{W}\]

\[\boxed{P\approx24\,\text{W}}\]

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