Two drivers G and H are at depths 20m and 40m, respectively below the water surface in a lake. The pressure on G is O1 1 while the pressure on H is P 2 , If...
Question 1 Report
Two drivers G and H are at depths 20m and 40m, respectively below the water surface in a lake. The pressure on G is O1
while the pressure on H is P
, If the atmospheric pressure is equivalent to 10m2
of water, then the value of P1
/P
2 is
Answer Details
The pressure at a depth h below the surface of a liquid can be calculated using the equation:
P = P_atmosphere + ρgh
where P_atmosphere is the atmospheric pressure, ρ is the density of the liquid, g is the acceleration due to gravity, and h is the depth below the surface.
Given that the atmospheric pressure is 10m^2, the pressure at a depth of 20m and 40m below the surface of the lake would be:
P1 = 10 + ρgh = 10 + 1000 * 9.8 * 20 = 10 + 1960
P2 = 10 + ρgh = 10 + 1000 * 9.8 * 40 = 10 + 3920
So, P2 / P1 = 3920 / 1960 = 2.00
Therefore, the value of P2 / P1 2 is 2.00.
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