The mean age of n men in a club is 50 years. Two men aged 55 and 63 years left the club, and the mean age reduced by 1 year. Find the value of n.

Assessment: WAEC SSCE - Further Mathematics - 2006 (Objective) Subject: Further Mathematics

Question 1 Report

The mean age of n men in a club is 50 years. Two men aged 55 and 63 years left the club, and the mean age reduced by 1 year. Find the value of n.

Answer Details
Let's denote the sum of ages of the n men in the club by S. Then we know that: Mean age of n men = S/n = 50 Multiplying both sides by n, we get: S = 50n After two men aged 55 and 63 years leave the club, the sum of ages of the remaining men becomes: S' = S - 55 - 63 = 50n - 118 The new mean age is reduced by 1 year, so we have: S'/(n-2) = 50 - 1 Simplifying this equation and substituting S', we get: (50n - 118)/(n-2) = 49 Multiplying both sides by n-2, we get: 50n - 118 = 49(n-2) Simplifying this equation, we get: n = 20 Therefore, there were originally 20 men in the club.

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