Given that \(\frac{1}{8^{2y - 3y}} = 2^{y + 2}\).

Question 1 Report

Given that \(\frac{1}{8^{2y - 3y}} = 2^{y + 2}\).

\(\frac{1}{5}\)

\(\frac{7}{8}\)

1

\(1\frac{1}{5}\)

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