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Given that \(\frac{1}{8^{2y - 3y}} = 2^{y + 2}\).
Question 1
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Given that \(\frac{1}{8^{2y - 3y}} = 2^{y + 2}\).
\(\frac{1}{5}\)
\(\frac{7}{8}\)
1
\(1\frac{1}{5}\)
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