A force of 32 N is applied to an object of mass m kg which is at rest on a smooth horizontal surface. If the acceleration produced is 8\(ms^{-2}\), find the...

A force of 32 N is applied to an object of mass m kg which is at rest on a smooth horizontal surface. If the acceleration produced is 8\(ms^{-2}\), find the value of m.

Answer Details

We can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration. The formula can be written as F = ma, where F is the force, m is the mass, and a is the acceleration. In this case, the force acting on the object is 32 N, and the acceleration produced is 8 \(ms^{-2}\). Since the object is at rest, its initial velocity is zero. So, we can use the formula F = ma to find the value of m. Rearranging the formula, we get m = F/a. Substituting the given values, we get m = 32 N / 8 \(ms^{-2}\) = 4 kg. Therefore, the value of m is 4 kg.