(a) State Faraday’s second law of electrolysis. (b) An electric charge of 9.6 x 10\(^4\) C liberates 1 mole of substance containing 6.0 x 10\(^{23}\) atoms....
Question 1 Report
(a) State Faraday’s second law of electrolysis.
(b) An electric charge of 9.6 x 10\(^4\) C liberates 1 mole of substance containing 6.0 x 10\(^{23}\) atoms. Determine the value of the electronic charge
Answer Details
(a) Faraday's second law of electrolysis
When the same quantity of electricity is passed through different electrolytes, the masses of the different substances liberated (or deposited) are directly proportional to their chemical equivalents (that is, to the ratio of their relative atomic mass to valency).
(b) Value of the electronic charge
The substance is monovalent, so each atom is discharged by one electron. One mole contains \(N = 6.0\times10^{23}\) atoms and is liberated by a charge \(Q = 9.6\times10^{4}\ \text{C}\).
The charge carried by one electron (one atom) is:
\[ e = \frac{Q}{N} = \frac{9.6\times10^{4}}{6.0\times10^{23}} \] \[ e = 1.6\times10^{-19}\ \text{C} \]The value of the electronic charge is \(1.6\times10^{-19}\ \text{C}\).
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