Question 1 Report
If the area of \( \triangle PQR \) above is \(12\sqrt{3}\text{ cm}^2\), find the value of q?
Answer Details
Let A denote the area of △ △ PQR, then A = 12bh 1 2 b h
Using Sin 60∘ ∘ = hq h q
h = q sin 60∘ ∘
So A = 12b(qsin60o) 1 2 b ( q sin 60 o )
12√3=12×8×q×√33 3 = 1 2 × 8 × q × 3 3
12√3 3 - 2q√3 3
q = 122=6 12 2 = 6 cm
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