Given that log 2 = 0.3010, log 7 = 0.8451. Evaluate log 112.
Answer Details
We can use the rule that says log(ab) = log(a) + log(b) to solve this problem. First, let's factor 112 into its prime factors: 112 = 2 x 2 x 2 x 2 x 7 Using the above rule, we can write: log(112) = log(2 x 2 x 2 x 2 x 7) = log(2) + log(2) + log(2) + log(2) + log(7) Now we can substitute the given values of log(2) and log(7) into the equation: log(112) = 0.3010 + 0.3010 + 0.3010 + 0.3010 + 0.8451 = 2.0491 Therefore, the answer is 2.0491.