The table gives information about four homologous series of organic compounds. Homologous series Functional group General formula Name of first member alkan...

Assessment: Chemistry 0620 | Paper 4 Mock 01 | Theory (Extended) Subject: Chemistry - 0620

Question 1 Report

The table gives information about four homologous series of organic compounds.

Homologous seriesFunctional groupGeneral formulaName of first member
alkanesnone (C-C single bonds)CnH2n+2methane
alkenesC=C double bond...........ethene
alcohols...........CnH2n+1OHmethanol
carboxylic acids-COOHCnH2n+1COOH...........

(a) Complete the three gaps in the table: the general formula of the alkenes, the functional group of the alcohols and the name of the first member of the carboxylic acids. [3]
(b) State the name given to the -COOH functional group of the carboxylic acids. [1]
(c) Name the functional group that is present in every alkene. [1]
(d) Give the general formula of the carboxylic acids. [1]
(e) Name the second member of the carboxylic acid series. [1]
(f) State the difference between an alkane molecule and an alkene molecule in terms of the bonding between the carbon atoms. [2]
(g) Deduce the molecular formula of the alkene that contains five carbon atoms. [1]
(h) Explain why all the members of a single homologous series have similar chemical properties. [2]

Answer Details

This question is built around the idea of a homologous series: a family of compounds with the same functional group, the same general formula, and a gradual change in physical properties. Fill the gaps and then explain that idea.

(a) The three missing entries are:

  • general formula of the alkenes: CnH2n [1]
  • functional group of the alcohols: the hydroxyl (-OH) group [1]
  • first carboxylic acid: methanoic acid [1]

(b) The -COOH group is called the carboxyl group [1].

(c) Every alkene contains a carbon-carbon double bond, C=C [1].

(d) The general formula of the carboxylic acids is CnH2n+1COOH (the form CnH2nO2 is also accepted) [1].

(e) After methanoic acid, the second member is ethanoic acid [1].

(f) In an alkane the carbon atoms are joined only by single (C-C) bonds, so it is saturated [1]; in an alkene at least one pair of carbons is joined by a double (C=C) bond, so it is unsaturated [1].

(g) For five carbons in the alkenes, \( \text{H} = 2n = 2(5) = 10 \), so the formula is C5H10 [1].

(h) All members of one homologous series have the same functional group [1], and it is the functional group that determines the chemical reactions, so they react in the same way [1].

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