A night train leaves Warsaw at \(21\,47\) and arrives in Prague at \(06\,13\) the next morning. Work out the journey time in hours and minutes.
Question 1 Report
A night train leaves Warsaw at \(21\,47\) and arrives in Prague at \(06\,13\) the next morning.
Work out the journey time in hours and minutes.
Answer Details
The journey crosses midnight, so it is safest to split the time into the part before midnight and the part after it rather than subtracting the clock readings directly.
- From \(21\,47\) to \(24\,00\) is \(2\) h \(13\) min.
- From \(00\,00\) to \(06\,13\) is a further \(6\) h \(13\) min [M1].
- Add: \(2\) h \(13\) min \(+\) \(6\) h \(13\) min \(=8\) h \(26\) min [A1].
The journey time is \(8\) hours \(26\) minutes.
Subtracting \(21\,47\) from \(06\,13\) as if they were ordinary numbers gives a negative or nonsensical result, because clock time is not decimal. If you prefer a calculator, \(06\,13\) the next day is \(30.21\overline{6}\) hours after midnight of the first day and \(21\,47\) is \(21.78\overline{3}\) hours, and the difference \(8.4\overline{3}\) hours converts to \(8\) h \(26\) min since \(0.4\overline{3}\times 60=26\). Remember that \(8.43\) hours is not \(8\) h \(43\) min.
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