WAEC SSCE - General Mathematics - 2000…

Question 1 Report

Find the equation whose roots are -8 and 5

$x^2 + 13x + 40=0$

$x^2 - 13x - 40=0$

$x^2 - 3x +40=0$

$x^2 + 3x - 40=0$

Quadratic Equations

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Question 2 Report

The height of a pyramid on square base is 15cm. if the volume is 80cm^3, find the area of the square base.

8cm²

9.6cm²

16cm²

25cm²

Answer Details

The volume of a pyramid is given by the formula V = (1/3)Bh, where B is the area of the base and h is the height of the pyramid. In this question, we are given the volume of the pyramid and its height, and we are asked to find the area of the square base. Let's substitute the given values into the formula for the volume of a pyramid: 80 = (1/3)B(15) Multiplying both sides by 3 gives: 240 = 15B Dividing both sides by 15 gives: 16 = B So the area of the square base is 16 cm². Therefore, the correct answer is: 16cm².

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Volumes

Coordinate Geometry

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Question 3 Report

Make t the subject of formula $k = m\sqrt{\frac{t-p}{r}}$

$\frac{rk^2 + p}{m^2}$

$\frac{rk^2+pm^2}{m^2}$

$\frac{rk^2-p}{m^2}$

$\frac{rk^2-p^2}{m^2}$

Answer Details

To make t the subject of the given formula, we need to isolate t on one side of the equation. Let's begin by squaring both sides of the equation: \begin{align*} k &= m\sqrt{\frac{t-p}{r}}\\ k^2 &= m^2\frac{t-p}{r}\\ k^2r &= m^2(t-p)\\ \end{align*} Next, we'll isolate the t term by dividing both sides of the equation by m^2 and adding p: \begin{align*} k^2r &= m^2(t-p)\\ \frac{k^2r}{m^2}+p &= t\\ \end{align*} Therefore, we have: $$t = \frac{k^2r}{m^2}+p$$ Hence, the answer is option $\mathbf{(B)}$ $\frac{rk^2+pm^2}{m^2}$.

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Question 4 Report

Find the missing number in the addition of the following numbers, in base seven
$\begin{matrix}
4 & 3 & 2 & 1\\
1 & 2 & 3 & 4\\
* & * & * & *\\
1&2&3&4&1
\end{matrix}$

3453

5556

6016

13453

Number Bases

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Question 5 Report

Given that $log_4 x = -3$, find x.

$\frac{1}{81}$

$\frac{1}{64}$

64

81

Answer Details

The given equation is $\log_4 x = -3$. We know that $\log_a b = c$ is equivalent to $a^c = b$. Using this property, we have: $$4^{-3} = x$$ Simplifying the right-hand side, we get: $$\frac{1}{4^3} = x$$ Since $4^3 = 64$, we have: $$\frac{1}{64} = x$$ Therefore, the answer is $\frac{1}{64}$.

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Logarithms

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Question 6 Report

If x varies inversely as y and $x = \frac{2}{3}$ when y = 9, find the value of y when $x=\frac{3}{4}$

$\frac{1}{18}$

$\frac{8}{81}$

$\frac{9}{2}$

8

Answer Details

The problem statement tells us that x and y are inversely proportional, which means that their product is constant. We can write this relationship as: xy = k where k is a constant. We are also given that when y = 9, x = 2/3. Substituting these values into the equation above, we get: (2/3)(9) = k k = 6 Now we can use this value of k to find y when x = 3/4: (3/4)y = 6 y = (6 x 4)/3 y = 8 Therefore, when x = 3/4, y = 8. So the answer is option (D).

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Variation

Modular Arithmetic

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Question 7 Report

Simplify $\left(\frac{16}{81}\right)^{-\frac{3}{4}}\times \sqrt{\frac{100}{81}}$

$\frac{80}{243}$

$\frac{1}{64}$

$\frac{25}{6}$

$\frac{15}{4}$

Answer Details

We can simplify the given expression using the rules of exponents and radicals as follows: \begin{align*} \left(\frac{16}{81}\right)^{-\frac{3}{4}}\times \sqrt{\frac{100}{81}} &= \left(\frac{81}{16}\right)^{\frac{3}{4}}\times \frac{10}{9} \\ &= \left[\left(\frac{3^4}{2^4}\right)^{\frac{1}{4}}\right]^3 \times \frac{10}{9} \\ &= \left(\frac{3}{2}\right)^3 \times \frac{10}{9} \\ &= \frac{27 \times 10}{8 \times 9} \\ &= \frac{15}{4} \end{align*} Therefore, the simplified expression is $\frac{15}{4}$. So, the answer is option (D).

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Question 8 Report

The bar chart shows the distribution of marks scored by a group of students in a test. Use the chart to answer the question below
How many students took the test?

38

32

15

11

Representation Of Data

Measures Of Location

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Question 9 Report

Form an inequality for a distance d meters which is more than 18m, but not more than 23m

18 ≤ d ≤ 23

18 < d ≤ 23

18 ≤ d < 23

d < 18 or d > 23

Answer Details

The inequality for a distance d meters which is more than 18m, but not more than 23m can be written as: 18 < d ≤ 23 Here, the lower limit is exclusive because the distance should be more than 18m and the upper limit is inclusive because the distance should not be more than 23m. This means that any value of d that is greater than 18m and less than or equal to 23m satisfies this inequality. Therefore, the correct option is: 18 < d ≤ 23

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Linear Inequalities

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Question 10 Report

A tap leaks at the rate of 2cm$^3$ per seconds. How long will it take the tap to fill a container of 45 liters capacity? (1 liters = 1000cm$^3$)

8 hours

6hr 15min

4hr 25min

3hr

Answer Details

The container has a capacity of 45 liters = 45,000 cm$^3$. The tap leaks at the rate of 2cm$^3$ per second. Therefore, the time taken to fill the container can be found by dividing the volume of the container by the rate of the tap: Time = Volume / Rate Time = 45,000 cm$^3$ / 2 cm$^3$/s Time = 22,500 seconds We can convert the seconds to hours and minutes as follows: 22,500 seconds = 6 hours 15 minutes Therefore, the answer is 6hr 15min.

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Read lesson note on Integration (JAMB)

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Representation Of Data

Integration

Probability

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Question 11 Report

Express $\frac{7}{19}$ as a percentage, correct to one decimal place

2.7%

3.7%

27.1%

36.8%

Answer Details

To express a fraction as a percentage, we can multiply the fraction by 100. So, \begin{align*} \frac{7}{19} \times 100 &= 36.842 \\ &\approx 36.8 \quad \text{(to one decimal place)}. \end{align*} Therefore, $\frac{7}{19}$ as a percentage, correct to one decimal place, is 36.8%. Therefore, the correct option is (c) 36.8%.

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Positive And Negative Integers, Rational Numbers

Modular Arithmetic

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Question 12 Report

In the diagram, PQRS is a circle center O. PQR is a diameter and ∠PRQ = 40°. Calculate ∠QSR.

30^o

40^o

45^o

50^o

Answer Details

Since PQR is a diameter, it follows that ∠PQR = 90°. Since the sum of the angles in a triangle is 180°, then ∠QRP = 180° - 90° - 40° = 50°. Angles in the same segment of a circle are equal. Therefore, ∠QSR = ∠QRP = 50°. Hence, the answer is option (D) 50°.

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Circles

Angles Of Elevation And Depression

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Question 13 Report

The bar chart shows the distribution of marks scored by a group of students in a test. Use the chart to answer the question below
How many students scored 4 marks and above?

15

11

10

17

Answer Details

Looking at the bar chart, we can see that the horizontal axis represents the marks scored by the students, and the vertical axis represents the number of students who scored those marks. To find out how many students scored 4 marks and above, we need to add up the number of students who scored in the bars corresponding to 4, 5, 6, 7, and 8 marks. Adding up the heights of these bars, we get: 2 + 4 + 5 + 4 + 2 = 17 Therefore, 17 students scored 4 marks and above in the test. Hence, the answer is option D: 17.

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Read lesson note on Measures Of Location (JAMB)

Representation Of Data

Measures Of Location

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Question 14 Report

If the interior angles of hexagon are 107°, 2x°, 150°, 95°, (2x-15)° and 123°, find x.

$57\frac{1}{2}^{\circ}$

$65^{\circ}$

$106^{\circ}$

$120^{\circ}$

Answer Details

The sum of the interior angles of a hexagon is given by the formula (n-2) x 180, where n is the number of sides of the polygon. Therefore, for a hexagon (6 sides), the sum of the interior angles is (6-2) x 180 = 720 degrees. We are given five of the six interior angles of the hexagon: 107°, 2x°, 150°, 95°, and (2x-15)°. We can use these angles to set up an equation and solve for x: 107° + 2x° + 150° + 95° + (2x-15)° + sixth angle = 720° Simplifying, we get: 339° + 4x = 720° Subtracting 339 from both sides, we get: 4x = 381° Dividing both sides by 4, we get: x = 95.25° None of the answer choices match this exact value, but we can round it to the nearest degree to get 95°, which corresponds to choice (b). Therefore, the answer is: - $65^{\circ}$

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Triangles And Polygons

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Question 15 Report

Find the volume (in cm$^3$) of the solid shown above

100cm³

150cm³

175cm³

250cm³

Volumes

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Question 16 Report

A tree is 8km due south of a building. Kofi is standing 8km west of the tree. How far is Kofi from the building?

4√2km

8km

8√2km

16km

Answer Details

We can use the Pythagorean theorem to solve this problem. Kofi is 8 km west of the tree, which means he is directly north of the building. We can draw a right-angled triangle with the building at the southeast corner, the tree at the southwest corner, and Kofi at the north corner. The distance between the building and the tree is the hypotenuse of the right-angled triangle, and the distance between Kofi and the tree is one of the legs. Using the Pythagorean theorem, we can find the length of the hypotenuse: hypotenuse² = leg₁² + leg₂² In this case, leg₁ is 8 km (the distance between Kofi and the tree), and leg₂ is 8 km (the distance between the tree and the building): hypotenuse² = 8² + 8² hypotenuse² = 128 hypotenuse = √128 hypotenuse = 8√2 Therefore, Kofi is 8√2 km away from the building. Option C, 8√2km, is the correct answer.

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Read lesson note on Angles And Intercepts On Parallel Lines (WAEC)

Sine, Cosine And Tangent Of An Angle

Coordinate Geometry

Angles And Intercepts On Parallel Lines

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Question 17 Report

Express 398753 correct to three significant figures

398000

398700

398800

399000

Answer Details

To express 398753 correct to three significant figures, we need to look at the first three digits of the number and round it off accordingly. The first three digits of 398753 are 398. The fourth digit, which is 7, is greater than or equal to 5, so we need to round up the third digit. Therefore, when we round off 398753 to three significant figures, we get: $$ 398753 \approx 399000 $$ So, the correct answer is 399000.

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Read lesson note on Number Bases (JAMB)

Fractions, Decimals And Approximations

Number Bases

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Question 18 Report

Find the value of x such that the expression $\frac{1}{x}+\frac{4}{3x}-\frac{5}{6x}+1$ equals zero

$\frac{1}{6}$

$\frac{1}{4}$

$\frac{-3}{2}$

$\frac{-7}{6}$

Algebraic Fractions

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Question 19 Report

If $104_x = 68$, find the value of x

5

7

8

9

Answer Details

To find the value of x, we need to convert the given number from base-x to base-10, and then solve for x. First, let's write out what the given number means in expanded form: \begin{align*} 104_x &= 1 \times x^2 + 0 \times x^1 + 4 \times x^0 \\ &= x^2 + 4 \end{align*} We're also told that this equals 68, so we can set up an equation: $$x^2 + 4 = 68$$ Solving for x, we get: \begin{align*} x^2 &= 64 \\ x &= \pm 8 \end{align*} Since x is the base of a number system, it must be a positive integer. Therefore, the only possible solution is x = 8. Therefore, the value of x is 8.

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Number Bases

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Question 20 Report

If the simple interest on N2000 after 9 months is N60, at what rate per annum is the interest charged?

$2\frac{1}{4}$%

4%

5%

6%

Answer Details

Given: Simple Interest (SI) = N60, Principal (P) = N2000, Time (T) = 9 months. We can use the formula for simple interest to find the interest rate per annum. Simple Interest = (P * R * T) / 100 Where R is the interest rate per annum. Converting the time in months to years, we get: T = 9/12 = 0.75 years Substituting the values in the formula, we get: 60 = (2000 * R * 0.75) / 100 Simplifying the equation, we get: R = (60 * 100) / (2000 * 0.75) R = 4 Therefore, the interest rate per annum is 4%. Note that this is a simple interest calculation and not a compound interest calculation.

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Sine, Cosine And Tangent Of An Angle

Modular Arithmetic

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Question 21 Report

The length of the parallel sides of a trapezium are 5cm and 7cm. If its area is 120cm$^2$, find the perpendicular distance between the parallel sides

5.0cm

6.9cm

10.0cm

20.0cm

Answer Details

The area of a trapezium is given by the formula: $$\text{Area} = \frac{1}{2}(a+b)h$$ where $a$ and $b$ are the parallel sides of the trapezium and $h$ is the perpendicular distance between them. In this question, we are given that $a = 5\text{ cm}$, $b = 7\text{ cm}$, and $\text{Area} = 120\text{ cm}^2$. We need to find $h$. Using the formula above, we can rearrange it to get $h$ as the subject: $$h = \frac{2\text{Area}}{a+b}$$ Substituting the given values, we get: $$h = \frac{2(120)}{5+7} = \frac{240}{12} = 20$$ Therefore, the perpendicular distance between the parallel sides is $20\text{ cm}$. The answer is not among the options given, so it is likely there was an error in one of the values or options presented.

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Lengths And Perimeters

Areas

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Question 22 Report

Given that \(27^{(1+x)}=9,)\ find x

-3

$\frac{-1}{3}$

$\frac{5}{3}$

2

Answer Details

Taking the natural logarithm of both sides, we have: \begin{align*} \ln(27^{1+x}) &= \ln 9 \\ (1+x)\ln 27 &= \ln 9 \\ (1+x)\ln(3^3) &= \ln(3^2) \\ (1+x)(3\ln 3) &= 2\ln 3 \\ 1+x &= \frac{2\ln 3}{3\ln 3} \\ 1+x &= \frac{2}{3} \\ x &= \frac{2}{3} - 1 \\ x &= -\frac{1}{3} \end{align*} Therefore, the answer is (b) $\frac{-1}{3}$.

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Indices

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Question 23 Report

The area of a circle is 38.5cm². Find its diameter [take $\pi = \frac{22}{7}$]

22cm

14cm

7cm

6cm

Answer Details

The formula for the area of a circle is given by A = πr², where A is the area and r is the radius of the circle. To find the diameter, we need to first find the radius. Given A = 38.5 cm² and π = 22/7, we can write: A = πr² 38.5 = (22/7) * r² Multiplying both sides by 7/22, we get: r² = (38.5 * 7) / 22 r² = 12.25 Taking the square root of both sides, we get: r = 3.5 The diameter is twice the radius, so: diameter = 2 * radius = 2 * 3.5 = 7 cm Therefore, the answer is option (C) 7cm.

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Question 24 Report

The probabilities that Kodjo and Adoga pass an examination are $\frac{3}{4}$ and $\frac{3}{5}$ respectively. Find the probability of both boys failing the examination

$\frac{1}{10}$

$\frac{3}{10}$

$\frac{9}{20}$

$\frac{2}{3}$

Answer Details

The probability of Kodjo passing the exam is $\frac{3}{4}$ and the probability of Adoga passing the exam is $\frac{3}{5}$. To find the probability of both boys failing the exam, we need to find the probability of Kodjo failing the exam and the probability of Adoga failing the exam, and then multiply these probabilities together. The probability of Kodjo failing the exam is $1 - \frac{3}{4} = \frac{1}{4}$. Similarly, the probability of Adoga failing the exam is $1 - \frac{3}{5} = \frac{2}{5}$. Therefore, the probability of both boys failing the exam is: $$ \frac{1}{4} \times \frac{2}{5} = \frac{2}{20} = \frac{1}{10} $$ So, the correct answer is $\frac{1}{10}$.

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Read lesson note on Surds (radicals) (WAEC)

Probability

Surds (radicals)

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Question 25 Report

The arc of a circle 50 cm long, subtends angle of 75° at the center of the circle. Find correct to 3 significant figures, the radius of the circle. Take $\pi = \frac{22}{7}$

8.74cm

38.2cm

61.2cm

76.4cm

Answer Details

To find the radius of the circle, we need to use the formula: $$ \text{length of arc} = \theta \frac{\pi r}{180} $$ where $\theta$ is the angle subtended by the arc at the center of the circle, $r$ is the radius of the circle, and $\pi$ is the mathematical constant pi. Substituting the given values, we get: $$ 50 = 75 \times \frac{\pi r}{180} $$ Simplifying the equation, we get: $$ r = \frac{50 \times 180}{75 \times \pi} \approx 38.2 \text{ cm (to 3 significant figures)} $$ Therefore, the correct answer is 38.2cm.

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Circles

Coordinate Geometry

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Question 26 Report

Solve the equation $3y^2 = 27y$

y = o or 3

y = 0 or 9

y = -3 or 3

y = 3 or 9

Answer Details

To solve the equation $3y^2 = 27y$, we can begin by factoring out the common factor of 3y from the left side of the equation: $$3y^2 - 27y = 0$$ Next, we can factor out 3y from each term: $$3y(y - 9) = 0$$ This equation can be solved by the Zero Product Property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero. Therefore, we have: $$3y = 0 \text{ or } y - 9 = 0$$ Solving each equation for y, we get: $$y = 0 \text{ or } y = 9$$ So the solution to the equation $3y^2 = 27y$ is: $$y = 0 \text{ or } y = 9$$ Therefore, the correct answer is: y = 0 or 9.

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Quadratic Equations

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Question 27 Report

In the diagram, PQS is a circle with center O. RST is a tangent at S and ?SOP = 96^o. Find ?PST

42^o

48^o

60^o

66^o

Circles

Angles Of Elevation And Depression

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Question 28 Report

Calculate the standard deviation of the following marks; 2, 3, 6, 2, 5, 0, 4, 2

1.5

1.7

1.8

1.9

Answer Details

To calculate the standard deviation of a set of data, we need to follow these steps: 1. Find the mean (average) of the data. 2. For each data point, subtract the mean and square the result. 3. Find the average of the squared differences (this is called the variance). 4. Take the square root of the variance to find the standard deviation. So, for the given data set {2, 3, 6, 2, 5, 0, 4, 2}, we can first find the mean: (mean) = (2+3+6+2+5+0+4+2)/8 = 24/8 = 3 Next, we can find the squared differences from the mean for each data point: (2-3)^2 = 1 (3-3)^2 = 0 (6-3)^2 = 9 (2-3)^2 = 1 (5-3)^2 = 4 (0-3)^2 = 9 (4-3)^2 = 1 (2-3)^2 = 1 Then we can find the average of these squared differences: (variance) = (1+0+9+1+4+9+1+1)/8 = 26/8 = 3.25 Finally, we take the square root of the variance to find the standard deviation: (standard deviation) = sqrt(3.25) ≈ 1.8 Therefore, the standard deviation of the given marks is approximately 1.8. So the correct option is (c) 1.8.

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Question 29 Report

Solve the equation 3 + 5x - 2x² = 0

$-\frac{1}{2},-3$

2, 3

-2, 3

$-\frac{1}{2},3$

Algebraic Expressions

Surds (radicals)

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Question 30 Report

Given that (2x + 7) is a factor of $2x^2 + 3x - 14$, find the other factor

x + 2

2 - x

x - 2

x + 1

Answer Details

To find the other factor, we need to use polynomial long division or synthetic division. But since the problem already tells us that (2x + 7) is a factor, we can use this information to simplify the problem. If (2x + 7) is a factor of $2x^2 + 3x - 14$, then we know that when we divide $2x^2 + 3x - 14$ by (2x + 7), the remainder is zero. This gives us the equation: $\frac{2x^2 + 3x - 14}{2x + 7} = x - 2$ Therefore, the other factor is (x - 2).

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Algebraic Expressions

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Question 31 Report

Each side of a regular convex polygon subtends an angle of 30° at its center. Calculate each interior angle

75^o

150^o

160^o

68^o

Answer Details

A regular convex polygon has equal angles and equal sides. Therefore, to calculate the interior angle of a regular convex polygon, we can use the formula: Interior angle = (n - 2) x 180 / n where n is the number of sides of the polygon. In this case, we know that each side subtends an angle of 30° at the center, which means that there are 12 sides in the polygon (since 360° / 30° = 12). Substituting this value into the formula, we get: Interior angle = (12 - 2) x 180 / 12 = 10 x 180 / 12 = 150° Therefore, each interior angle of the regular convex polygon is 150°. The answer is.

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Indices

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Question 32 Report

In the diagram, AB is a vertical pole and BC is horizontal. If |AC| = 10m and |BC| = 5m, calculate the angle of depression of C from A

63^o

60^o

45^o

27^o

Answer Details

The angle of depression of C from A is the angle formed between the line of sight from A to C and the horizontal line. This angle can be found using trigonometry. First, we can find the length of AB by using the Pythagorean theorem: |AB| = √(|AC|² - |BC|²) = √(10² - 5²) = √75 = 5√3 Next, we can find the tangent of the angle of depression: tan(θ) = |BC| / |AB| = 5 / (5√3) = √3 / 3 Finally, we can find the angle itself by taking the inverse tangent (or arctangent) of this value: θ = tan⁻¹(√3 / 3) ≈ 30° Therefore, the angle of depression of C from A is approximately 30°. The answer closest to this value is, 60°.

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Bearings

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Question 33 Report

A bicycle wheel of radius 42cm is rolled over a distance 66 meters. How many revolutions does it make?[Take $\pi = \frac{22}{7}$]

2.5

5

25

50

Answer Details

To calculate the number of revolutions made by the bicycle wheel, we need to find out the distance the wheel travels in one revolution, and then divide the total distance traveled by this distance. The circumference of the wheel is given by the formula C = 2πr, where r is the radius of the wheel. Substituting the given value, we get: C = 2 x (22/7) x 42 cm C = 264 cm Therefore, the distance the wheel travels in one revolution is 264 cm. To find the number of revolutions made by the wheel over a distance of 66 meters, we first need to convert 66 meters to centimeters. 1 meter = 100 centimeters, so 66 meters = 66 x 100 = 6600 centimeters. Now, we can find the number of revolutions made by the wheel by dividing the distance traveled by the distance traveled in one revolution: Number of revolutions = Total distance traveled / Distance traveled in one revolution Number of revolutions = 6600 cm / 264 cm Number of revolutions = 25 Therefore, the bicycle wheel makes 25 revolutions.

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Circles

Coordinate Geometry

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Question 34 Report

Given that the logarithm of a number is $\bar{1}.8732$, find, correct to 2 significant figures the square root of the number.

0.29

0.75

0.86

0.93

Logarithms

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Question 35 Report

Given that $x = -\frac{1}{2}and \hspace{1mm} y = 4 \hspace{1mm} evaluate \hspace{1mm} 3x^2y+xy^2$

-5

-1

4

11

Answer Details

Substituting the given values of x and y into the expression, we have: \begin{align*} 3x^2y+xy^2 &= 3\left(-\frac{1}{2}\right)^2(4) + \left(-\frac{1}{2}\right)(4)^2\\ &= 3\left(\frac{1}{4}\right)(4) + \left(-\frac{1}{2}\right)(16)\\ &= 3 + (-8)\\ &= -5 \end{align*} Therefore, the answer is -5.

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Algebraic Expressions

Modular Arithmetic

Fractions, Decimals, Approximations And Percentage

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Question 36 Report

The ages of three men are in the ratio 3:4:5. If the difference between the ages of the oldest and youngest is 18 years, find the sum of the ages of the three men

45 years

72 years

108 years

216 years

Answer Details

Let the ages of the three men be 3x, 4x, and 5x (since their ages are in the ratio 3:4:5). We know that the difference between the ages of the oldest and youngest is 18 years, so: 5x - 3x = 18 2x = 18 x = 9 Therefore, the ages of the three men are: - 3x = 27 years - 4x = 36 years - 5x = 45 years The sum of their ages is: 27 + 36 + 45 = 108 years. Therefore, the correct answer is 108 years.

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Read lesson note on Ratio, Proportions And Rates (WAEC)

Indices

Ratio, Proportions And Rates

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Question 37 Report

Which of the following statement is not true about a rectangle? I.Each diagonal cuts the rectangle into two congruent triangles. II. A rectangle has four lines of symmetry III. The diagonals intersect at right angles

I and II only

III only

II only

II and III only

Angles

Triangles And Polygons

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Question 38 Report

Which of the following bearings is equivalent to S50°W?

040^o

130^o

220^o

230^o

Answer Details

S50°W is the same as 220°, so the correct answer is. The bearing S50°W represents an angle of 50 degrees west of south, which is equivalent to a bearing of 180° + 50° = 230°. Therefore, is the correct answer.

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Bearings

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Question 39 Report

A car moves at an average speed of 30kmh$^{-1}$, how long does it take to cover 200 meters?

2.4 sec

24 sec

144 sec

240 sec

Answer Details

To find the time taken by the car to cover 200 meters, we need to use the formula: time = distance ÷ speed Here, the distance is 200 meters and the speed is 30 km/h. However, we need to convert the speed to meters per second (m/s) to get the answer in seconds. We know that 1 km = 1000 meters and 1 hour = 3600 seconds. So, 30 km/h = (30 x 1000) m / (3600 s) = 8.33 m/s (approx.) Now, we can substitute the values into the formula: time = distance ÷ speed = 200 m ÷ 8.33 m/s ≈ 24 seconds Therefore, the car takes 24 seconds to cover 200 meters. Hence, the answer is 24 sec.

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Read lesson note on Modular Arithmetic (WAEC)

Read lesson note on Angles (WAEC)

Sine, Cosine And Tangent Of An Angle

Modular Arithmetic

Angles

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Question 40 Report

A man bought a television set on hire purchase for N25,000, out of which he paid N10,000, if he is allowed to pay the balance in eight equal installments, find the value of each installment.

N1250

N1578

N1875

N3125

Answer Details

The man bought a television set on hire purchase for N25,000 and paid N10,000 initially. Therefore, the balance he needs to pay is N25,000 - N10,000 = N15,000. Since he is allowed to pay the balance in eight equal installments, the value of each installment will be: N15,000 ÷ 8 = N1875. Therefore, the value of each installment is N1875. The correct option is (c) N1875.

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Read lesson note on Areas (WAEC)

Volumes

Sine, Cosine And Tangent Of An Angle

Areas

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Question 41 Report

Simplify $\frac{1}{x-3}-\frac{3(x-1)}{x^2 - 9}$

$\frac{x-1}{x-3}$

$\frac{-2}{x+3}$

$\frac{x-1}{x+3}$

$\frac{4x}{x^2-9}$

Algebraic Fractions

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Question 42 Report

Given that p varies directly as q while q varies inversely as r, which of the following statements is true?

r varies directly as p

p varies inversely as r

p varies directly as r

q varies inversely as p

Answer Details

The statement "p varies inversely as r" is true. This means that as r increases, p decreases, and as r decreases, p increases. We know that p varies directly as q, so as q increases, p increases, and as q decreases, p decreases. Combining these two statements, we can say that as q increases, r decreases, and as q decreases, r increases. Therefore, p and r have an inverse relationship, meaning that p varies inversely as r. The other options are not true based on the information given.

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Variation

Inequalities

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Question 43 Report

A tree is 8km due south of a building. Kofi is standing 8km west of the tree. Find the bearing of Kofi from the building

315^o

270^o

225^o

135^o

Answer Details

To find the bearing of Kofi from the building, we need to draw a diagram and use trigonometry.

We know that the tree is 8km due south of the building, so we can draw a line segment from B to T, and label it 8km.

We also know that Kofi is standing 8km west of the tree, so we can draw a line segment from K to T, and label it 8km.

        K
        |
        |
        | 8km
        T
       / \
      /   \
     /     \
    B-------T
         8km

Now, we can use trigonometry to find the bearing of Kofi from the building. We know that Kofi is west of the tree, so the bearing we want is the angle between the line segment BT and the line segment BK. We can use the tangent function to find this angle:

tan(theta) = opposite / adjacent

tan(theta) = BT / BK

tan(theta) = 8km / 8km

theta = tan^-1(1)

theta ≈ 45°

So the angle between BT and BK is approximately 45 degrees. Since Kofi is west of the tree, we know that the bearing of Kofi from the building is 180 degrees plus 45 degrees, or 225 degrees.

Therefore, the answer is (c) 225^o.

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Bearings

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Question 44 Report

In the diagram, |PQ| = |PS| Which of the following statements is true?

?QPS = QRS

|PO| = |RO|

QR||PS

?PQR=?PSR

Answer Details

Since |PQ| = |PS|, we know that triangle PQS is an isosceles triangle. Therefore, the angles opposite the equal sides are equal, which means that ?QPS = ?PSQ.

Now, let's look at the answer choices:

?QPS = QRS: We cannot determine this from the information given. We do not know anything about the angle QRS.
|PO| = |RO|: We cannot determine this from the information given. We do not have any information about points P, O, and R.
QR||PS: We cannot determine this from the information given. We do not have any information about whether QR and PS are parallel or not.
?PQR = ?PSR: Since |PQ| = |PS|, we know that triangle PQS is an isosceles triangle. Therefore, ?PQS = ?PSQ. Also, since |PQ| = |PS| and PQRS is a parallelogram, we know that |QR| = |PS|. Therefore, triangle PSR is also an isosceles triangle, and ?SPR = ?PSR. Finally, since PQRS is a parallelogram, we know that ?PQR = ?SPR. Therefore, ?PQR = ?PSR.

So the correct answer is ?PQR = ?PSR.

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Read lesson note on Triangles And Polygons (WAEC)

Circles

Angles And Intercepts On Parallel Lines

Triangles And Polygons

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Question 45 Report

simplify $\frac{10}{\sqrt{32}}$

$\frac{5}{4}\sqrt{2}$

$\frac{4}{5}\sqrt{2}$

$\frac{5}{16}\sqrt{2}$

$\frac{16}{5}\sqrt{2}$

Answer Details

We can simplify $\frac{10}{\sqrt{32}}$ by rationalizing the denominator, which means we multiply both the numerator and denominator by the same number so that the denominator becomes a rational number (i.e., a number that can be written as a fraction). In this case, we can multiply the numerator and denominator by $\sqrt{32}$, since $\sqrt{32} = \sqrt{16 \times 2} = \sqrt{16} \times \sqrt{2} = 4\sqrt{2}$. So we have: $$\frac{10}{\sqrt{32}} \times \frac{\sqrt{32}}{\sqrt{32}} = \frac{10\sqrt{32}}{32} = \frac{5\sqrt{2}}{4}$$ Therefore, the answer is $\frac{5}{4}\sqrt{2}$.

Read lesson note on Positive And Negative Integers, Rational Numbers (WAEC)

Read lesson note on Surds (radicals) (WAEC)

Positive And Negative Integers, Rational Numbers

Surds (radicals)

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Question 46 Report

In the diagram, POS and ROT are straight lines, OPQR is a parallelogram. |OS| = |OT| and ∠OST = 50°. Calculate ∠OPQ.

160^o

140^o

120^o

100^o

Loci

Angles

Triangles And Polygons

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Question 47 Report

What fraction must be subtracted from the sum of $2\frac{1}{6}$ and $2\frac{7}{12}$ to give $3\frac{1}{4}$?

$\frac{1}{3}$

$\frac{1}{2}$

$1\frac{1}{6}$

$1\frac{1}{2}$

Algebraic Fractions

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Question 48 Report

Which of the following numbers is perfect cube?

350

504

950

1728

Answer Details

To determine which of the given numbers is a perfect cube, we need to find the cube root of each number and check if it is a whole number or not. The cube root of a number is a value that, when cubed, gives the original number. For example, the cube root of 27 is 3, because 3 x 3 x 3 = 27. Using a calculator or by hand, we can find that: - The cube root of 350 is approximately 7.327, which is not a whole number. - The cube root of 504 is approximately 8.005, which is not a whole number. - The cube root of 950 is approximately 9.685, which is not a whole number. - The cube root of 1728 is exactly 12, which is a whole number. Therefore, the only number that is a perfect cube from the options given is 1728.

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WAEC SSCE - General Mathematics - 2000 (Objective)